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0.464x^2+0.303x-0.30037=0
a = 0.464; b = 0.303; c = -0.30037;
Δ = b2-4ac
Δ = 0.3032-4·0.464·(-0.30037)
Δ = 0.64929572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.303)-\sqrt{0.64929572}}{2*0.464}=\frac{-0.303-\sqrt{0.64929572}}{0.928} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.303)+\sqrt{0.64929572}}{2*0.464}=\frac{-0.303+\sqrt{0.64929572}}{0.928} $
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